This week's maths problem

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Problem of the week

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On Friday of each week we will post a new maths challenge.
You may submit your solution by the following Thursday.
Each problem contains two different levels of difficulty. You will be awarded from 2 to 12 points for a full answer.
Each series contains 12 problems before the stage winner is determined.
Your score will be published here.

In each series we will give away 3 books as prices. The prices will be drawn by lot among the best ten participants of the series. The books are kindly sponsored by Buchdienst Rattei of Chemnitz.

Suggestions for problems are welcome.

Deadline is 20st of January 2022.


German version - Italian version - French version - Spanish version  Hungarian Version Russian version  --> 中文/Chinese <--

Series 59

problem 699

"Your dream last week prompted me to write down some more of Mr Fibonacci's numbers," Lisa said to Mike. Here are the first 25:
1, 1, 2, 3, 5, 8, 13, 21, 34, 55 , 89, 144, 233, 377, 610 , 987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368 and the 25th number is: 75025. The nice thing about the last number is, this 25th number also ends in 25."
That doesn't exist before, except for the first number 1 (and the 5).
There is another Fibonacci number to be found whose "number" matches the ending. 3 blue points.
You can also add the Fibonacci numbers one after another:
1+1=2, 1+1+2=4; 1+1+2+3=7, 1+1+2+3+5=12, ...
The regularity is not that difficult to recognize. How is this called and how can it be proved? (1 + 4 = 5) red points
Deadline for solution is the 20th. January 2022.

 

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adress:
Thomas Jahre
Stollberger Strasse 25
09119 Chemnitz
Germany


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Chemnitzer Schulmodell
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