This week's maths problem
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Problem of the week
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On Friday of each week we will post a new maths challenge.
You may submit your solution by the following Thursday.
Each problem contains two different levels of difficulty. You will be awarded from 2 to 12 points for a full answer.
Each series contains 12 problems before the stage winner is determined.
Your score will be published here.
In each series we will give away 3 books as prices. The prices will be drawn by lot among the best ten participants of the series. The books are kindly sponsored by Buchdienst Rattei of Chemnitz.
Suggestions for problems are welcome.
Deadline is 18th. April 2024.
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Series 66
problem 783
Maria and Bernd have been given two bars of chocolate, which can easily be divided into 24 pieces each.
"Let's work out how many times we have to break the bar until we have all 24 pieces individually," said Maria to Bernd. "But as good mathematicians, we should divide it perfectly!"
Broken pieces must not be placed on top of each other or next to each other on the first board.
Bernd notes an example:
First broken edge vertically between 2 and 3
Second broken edge horizontally between 7 and 13
Bernd now has three square pieces.
Third break edge vertical between 4 and 5.
Break the fourth and fifth edges to make 6 equal small squares with 4 pieces of chocolate each. From the small squares you can obtain the individual pieces with 3 fractions each. Bernd therefore needed 1+1+ 1 +1 +1 +1 +6*3 = 23 divisions.
Surely that's better, right? How do you get by with fewer fractions? There are 4 blue points for finding a path with fewer than 23 fractions or showing that there must always be 23.
On the second board, overlapping and adjacent lines are allowed. Bernd uses a hot and very sharp knife to help with the breaking.
How many divisions can you manage with this type? Do you get 4 red points for finding the smallest possible number of divisions?
Deadline for solution is the 18th. April 2024.
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adress:
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